Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - Chapter Review - Cumulative Review - Page 437: 11

Answer

$3-3\frac{\sqrt2}{2}$.

Work Step by Step

$\tan{\frac{\pi}{4}}-3\cos{\frac{\pi}{6}}+\csc{\frac{\pi}{6}}=1-3\frac{\sqrt2}{2}+2=3-3\frac{\sqrt2}{2}$. $\csc{\frac{\pi}{6}}=\dfrac{1}{\sin{\frac{\pi}{6}}}=\dfrac{1}{\frac{1}{2}}=2.$
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