Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - Chapter Review - Chapter Test - Page 436: 24

Answer

$-\dfrac{1}{2}$

Work Step by Step

First determine $x,y$: $(x,y)=(6,-3)$ $x=6$ $y=-3$ Compute $\tan\theta$: $\tan\theta=\dfrac{y}{x}=\dfrac{-3}{6}=-\dfrac{1}{2}$
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