Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - 6.6 Phase Shift; Sinusoidal Curve Fitting - 6.6 Assess Your Understanding - Page 430: 43

Answer

$y=\frac{2}{3}x-3$ or $2x-3y=9$

Work Step by Step

The given line has a slope of $m=\frac{2}{3}$ which is the same for the unknown parallel line. With point $(6,1)$, we have the new line equation as $y-1=\frac{2}{3}(x-6)$ or $y=\frac{2}{3}x-3$ or $2x-3y=9$
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