Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - 6.6 Phase Shift; Sinusoidal Curve Fitting - 6.6 Assess Your Understanding - Page 430: 42

Answer

$6.12\%$

Work Step by Step

Let the required interest rate be $r$, given $P=1500,A=1800,t=3,n=4$. We have $1800=1500(1+\frac{r}{4})^{4(3)} \longrightarrow 1+\frac{r}{4}=(\frac{18}{15})^{1/12} \longrightarrow r=4((\frac{18}{15})^{1/12}-1)\approx0.0612$ or $6.12\%$
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