Answer
$9$.
Work Step by Step
$f(x)=x^3-9x^2+3x-27=x^2(x-9)+3(x-9)=(x-9)(x^2+3)$, thus the real zero is $x=9$.
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 6 - Trigonometric Functions - 6.3 Properties of the Trigonometric Functions - 6.3 Assess Your Understanding - Page 397: 140
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