Answer
$x^2-14x+46$
Work Step by Step
Given $f(x)=x^2-3$ and $g(x)=x-7$, we have $(f\circ g)(x)=f(g(x))=(x-7)^2-3=x^2-14x+46$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 6 - Trigonometric Functions - 6.3 Properties of the Trigonometric Functions - 6.3 Assess Your Understanding - Page 397: 137
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