Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - 6.2 Trigonometric Functions: Unit Circle Approach - 6.2 Assess Your Understanding - Page 378: 19

Answer

$sin(t) =-\frac{1}{3}$, $cos(t) =\frac{2\sqrt 2}{3}$, $tan(t) =-\frac{\sqrt 2}{4}$, $cot(t) =-2\sqrt 2$, $sec(t) =\frac{3\sqrt 2}{4}$, $csc(t) =-3$.

Work Step by Step

Given $x=\frac{2\sqrt 2}{3}, y=-\frac{1}{3}, r=1$, we have: $sin(t)=y=-\frac{1}{3}$, $cos(t)=x=\frac{2\sqrt 2}{3}$, $tan(t)=\frac{y}{x}=-\frac{\sqrt 2}{4}$, $cot(t)=\frac{x}{y}=-2\sqrt 2$, $sec(t)=\frac{1}{x}=\frac{3\sqrt 2}{4}$, $csc(t)=\frac{1}{y}=-3$.
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