Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - 6.2 Trigonometric Functions: Unit Circle Approach - 6.2 Assess Your Understanding - Page 378: 18

Answer

$sin(t) =\frac{\sqrt 2}{2}$, $cos(t) =\frac{\sqrt 2}{2}$, $tan(t) =1$, $cot(t) =1$, $sec(t) =\sqrt 2$, $csc(t) =\sqrt 2$.

Work Step by Step

Given $x=\frac{\sqrt 2}{2}, y=\frac{\sqrt 2}{2}, r=1$, we have: $sin(t)=y=\frac{\sqrt 2}{2}$, $cos(t)=x=\frac{\sqrt 2}{2}$, $tan(t)=\frac{y}{x}=1$, $cot(t)=\frac{x}{y}=1$, $sec(t)=\frac{1}{x}=\sqrt 2$, $csc(t)=\frac{1}{y}=\sqrt 2$.
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