Answer
$5.79\text{mins}$
Work Step by Step
The arc length is: $PQ=A=90$ miles.
The linear speed is: $v=\frac{2\pi3559}{24}$ mph.
Hence $T=\frac{A}{v}=\dfrac{90}{\frac{2\pi3559}{24}}=0.0966\text{hrs}=0.0966\cdot60\text{mins}=5.79\text{mins}$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 6 - Trigonometric Functions - 6.1 Angles and Their Measure - 6.1 Assess Your Understanding - Page 364: 118
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