Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 6 - Trigonometric Functions - 6.1 Angles and Their Measure - 6.1 Assess Your Understanding - Page 364: 112

Answer

$66637.17\text{mph}$

Work Step by Step

The distance from the Sun to the Earth is: $r=9.29\cdot10^7$ miles. The Sun takes $365$ days($=365\cdot24$ hours) to make a revolution, hence its angular velocity is: $\omega=\frac{2\pi}{t}=\frac{2\pi}{365\cdot24}=7.173\cdot10^{-4}\frac{\text{rad}}{\text{hr}}.$ Therefore the linear velocity: $v=\omega r\\v=7.173\cdot10^{-4}(9.29\cdot10^7)=66637.17\text{mph}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.