Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 5 - Exponential and Logarithmic Functions - 5.5 Properties of Logarithms - 5.5 Assess Your Understanding - Page 306: 75

Answer

$\approx5.615$

Work Step by Step

Using The Change-of-Base Formula $\log_a{b}=\dfrac{\log_c{b}}{\log_c{a}}$ and then evaluating using a calculator gives $\log_{\sqrt 2}7=\dfrac{\log7}{\log{\sqrt2}}\approx5.615$
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