Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 5 - Exponential and Logarithmic Functions - 5.5 Properties of Logarithms - 5.5 Assess Your Understanding - Page 306: 102

Answer

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Work Step by Step

Step 1. $(\sqrt x+\sqrt {x-1})(\sqrt x-\sqrt {x-1})=(\sqrt x)^2-(\sqrt {x-1})^2=1$ Step 2. $log_a(\sqrt x+\sqrt {x-1})+log_a(\sqrt x-\sqrt {x-1})=log_a(\sqrt x+\sqrt {x-1})(\sqrt x-\sqrt {x-1})=log_a1=0$
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