Answer
$110$ decibels
Work Step by Step
$L(10^{-1})=10\log{\left(\frac{10^{-1}}{I_0}\right)}$.
Here, we have $I_0=10^{-12}$.
Hence, after substituting that in, we'd have:
$L(0^{-1})
\\=10\log{\left(\frac{10^{-1}}{10^{-12}}\right)}
\\=10\log{(10^{-1+12})}
\\=10\log{10^{11}}
\\=10\cdot11
\\=110$
