Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 5 - Exponential and Logarithmic Functions - 5.3 One-to-One Functions; Inverse Functions - 5.3 Assess Your Understanding - Page 282: 87



Work Step by Step

We know that $9=3^2$. Hence $9^x=25\\(3^2)^x=25\\3^{2x}=25\\\sqrt{3^{2x}}=\sqrt{25}\\\sqrt{(3^{x})^2}=\sqrt{5^2}\\3^x=5$
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