## Precalculus (10th Edition)

$3^x=5$
We know that $9=3^2$. Hence $9^x=25\\(3^2)^x=25\\3^{2x}=25\\\sqrt{3^{2x}}=\sqrt{25}\\\sqrt{(3^{x})^2}=\sqrt{5^2}\\3^x=5$