Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 5 - Exponential and Logarithmic Functions - 5.3 One-to-One Functions; Inverse Functions - 5.3 Assess Your Understanding - Page 282: 76

Answer

$\{2,4\}$.

Work Step by Step

As $125=5^3$, we have $5^{x^2+8}=(5^3)^{2x}$ or $5^{x^2+8}=5^{6x}$. Thus we have $x^2+8=6x$ or $x^2-6x+8=0$. This gives $x=2,4$ or $\{2,4\}$. Checking answers, they are both good.
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