Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 5 - Exponential and Logarithmic Functions - 5.3 Exponential Functions - 5.3 Assess Your Understanding - Page 283: 106


a)$568.68.$ b)$178.27.$

Work Step by Step

a) If $p(h)=760(e)^{-0.145h}$, then if $h=2$, $p(2)=760(e)^{-0.145\cdot2}=568.68.$ b) If $p(h)=760(e)^{-0.145h}$, then if $h=10$, $p(10)=760(e)^{-0.145\cdot10}=178.27.$
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