Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 5 - Exponential and Logarithmic Functions - 5.3 Exponential Functions - 5.3 Assess Your Understanding - Page 283: 105

Answer

a)$73.74\%.$ b)$46.69\%.$

Work Step by Step

a) If $p(n)=100(0.97)^n$, then if $n=10$, $p(10)=100(0.97^{10})=73.74\%.$ b) If $p(n)=100(0.97)^n$, then if $n=25$, $p(25)=100(0.97^{25})=46.69\%.$
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