Answer
See graph.
domain $(-\infty,\infty)$, range $(1,\infty)$, and horizontal asymptote $y=1$
Work Step by Step
Step 1. To obtain the graph of $f(x)=2^x+1$ from $y=2^x$, shift the curve 1 unit up. See graph.
Step 2. We can determine the domain is $(-\infty,\infty)$; the range is $(1,\infty)$; and the horizontal asymptote is $y=1$