Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 5 - Exponential and Logarithmic Functions - 5.3 Exponential Functions - 5.3 Assess Your Understanding - Page 281: 31

Answer

$F(x)=3\cdot2^x$.

Work Step by Step

The ratio of consecutive values is constant ($\dfrac{3}{\frac{3}{2}}=\frac{6}{3}=\frac{12}{6}=\frac{24}{12}=2$), hence, it an exponential function with a common ratio of $2$. But the difference of consecutive values is not constant ($6-3=3\ne12-6=6$), hence it is not a linear function. A function that models the data: (with a common ratio of $2$ and $F(0)=3\cdot2^0$) is $F(x)=3\cdot2^x$.
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