Answer
$f(x_1)\ne f(x_2)$
Work Step by Step
For one-to-one functions for each $x_1\ne x_2$, $f(x_1)\ne f(x_2).$ So the function values are distinct.
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 5 - Exponential and Logarithmic Functions - 5.2 One-to-One Functions; Inverse Functions - 5.2 Assess Your Understanding - Page 265: 5
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