Answer
Decreasing on $(-\infty,0)$ and increasing on $(0,\infty)$.
Work Step by Step
According to the graph, $f(x)=x^2$ is decreasing on $(-\infty,0)$ and increasing on $(0,\infty)$.
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 5 - Exponential and Logarithmic Functions - 5.2 One-to-One Functions; Inverse Functions - 5.2 Assess Your Understanding - Page 265: 2
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