Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 4 - Polynomial and Rational Functions - Chapter Review - Review Exercises - Page 244: 48

Answer

$-3,2, \pm i\frac{\sqrt 2}{2}$ $f(x)=2(x+ i\frac{\sqrt 2}{2})(x- i\frac{\sqrt 2}{2})(x+3)(x-2)$

Work Step by Step

Step 1. Based on the Rational Zeros Theorem, list possible rational zeros $\frac{p}{q}=\pm1,\pm2,\pm3,\pm6,\pm\frac{1}{2},\pm\frac{3}{2}$ Step 2. Use synthetic division to find one or more zeros $x=2,-3$ as shown in the figure. Step 3. Use to the quotient to solve $2x^2+1=0$ or $x^2=-\frac{1}{2}$, thus $x=\pm i\frac{\sqrt 2}{2}$ Step 4. We can factor the function as $f(x)=2(x+ i\frac{\sqrt 2}{2})(x- i\frac{\sqrt 2}{2})(x+3)(x-2)$
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