Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 4 - Polynomial and Rational Functions - Chapter Review - Review Exercises - Page 244: 45

Answer

$-2,1,4$ $f(x)=(x+2)(x-1)(x-4)$

Work Step by Step

Step 1. Based on the Rational Zeros Theorem, list possible rational zeros $\frac{p}{q}=\pm1,\pm2,\pm4,\pm8$ Step 2. Use synthetic division to find one or more zeros $x=1$ as shown in the figure. Step 3. Use to the quotient to solve $x^2-2x-8=0$ or $(x+2)(x-4)=0$, thus $x=-2,4$ Step 4. We can factor the function as $f(x)=(x+2)(x-1)(x-4)$
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