Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 4 - Polynomial and Rational Functions - 4.6 Complex Zeros; Fundamental Theorem of Algebra - 4.6 Assess Your Understanding - Page 241: 50

Answer

$x=-22$

Work Step by Step

Substitute $5$ to $f(x)$ to obtain: $f(x)=\sqrt{3-x}\\ 5=\sqrt{3-x}\\ 5^2=(\sqrt{3-x})^2\\ 25=3-x\\ x=3-25\\ x=-22$
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