Answer
$\pm1,\pm i$
$f(x)=(x+1)(x-1)(x+ i)(x- i)$
Work Step by Step
Step 1. Factor the function $f(x)=x^4-1=(x^2+1)(x+1)(x-1)$, thus we have zero(s) $x=\pm1$
Step 2. Solve $x^2+1=0$ to get $x=\pm i$
Step 3. Thus $f(x)=(x+1)(x-1)(x+ i)(x- i)$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 4 - Polynomial and Rational Functions - 4.6 Complex Zeros; Fundamental Theorem of Algebra - 4.6 Assess Your Understanding - Page 241: 32
Update this answer!
You can help us out by revising, improving and updating this answer.
Update this answerAfter you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.
