Answer
$0,6,\frac{11}{4}$
Work Step by Step
Step 1 Find zeros of $f(x)=4x^3-11x^2-26x+24$ as $x=-2,4,\frac{3}{4}$ (see figure).
Step 2. As $f(x-2)$ can be obtained from $f(x)$ by shifting the curve 2 units to the right, we can find zeros for $f(x-2)$ as $x=0,6,\frac{11}{4}$