Answer
$\{ \frac{-1\pm\sqrt {13}}{2}\}$
Work Step by Step
Use the quadratic formula, we have $x=\frac{-1\pm\sqrt {1^2-4(1)(-3)}}{2}=\frac{-1\pm\sqrt {13}}{2}$ or $\{ \frac{-1\pm\sqrt {13}}{2}\}$
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