Answer
$(3x+2)(2x-1)$
Work Step by Step
$6x^2+x-2=(3x+2)(2x-1)$ by using the quadratic formula. ($\frac{-b\pm\sqrt{b^2-4ac}}{2a}$ when the equation is in the form: $ax^2+bx+c=0$.)
Alternatively, the constant must be constructed by multiplying $2$ and $-1$, hence the factor will be in the form of $(ax+2)(bx-1)=abx^2+(2b-a)x-2$.
Therefore $2b-a=1\\a=2b-1.$
$ab=6\\(2b-1)b=6\\b=2$
