Answer
(a) $(-\infty,2)U(2,\infty)$
(b) $x=0$
Work Step by Step
Given $R(x)=\frac{x(x-2)^2}{x-2}=x(x-2), (x\ne2)$
(a) we can find the domain as $(-\infty,2)U(2,\infty)$
(b) To find the x-intercepts, let $R(x)=0$, we have $x(x-2)=0$ and we only have $x=0$ or $(0,0)$
