Answer
vertical asymptote $none$,
horizontal asymptote $none$,
oblique asymptote $none$.
Work Step by Step
Step 1. Factor the function $R(x)=\frac{8x^2+26x-7}{4x-1}=\frac{(2x+7)(4x-1)}{4x-1}=2x+7, (x\ne\frac{1}{4})$, thus it is a line with a hole.
Step 2. we can find the vertical asymptote $none$,
Step 3. we can find the horizontal asymptote $none$,
Step 4. we can find the oblique asymptote $none$.
