Answer
vertical asymptotes $x=-1$ and $x=1$,
horizontal asymptote $y=0$,
oblique asymptote $none$.
Work Step by Step
Step 1. Factor the function $T(x)=\frac{x^3}{x^4-1}=\frac{x^3}{(x^2+1)(x+1)(x-1)}$,
Step 2. we can find the vertical asymptotes $x=-1$ and $x=1$,
Step 3. we can find the horizontal asymptote $y=0$,
Step 4. we can find the oblique asymptote $none$.
