Answer
$3x+3$, $2x^2-3x-3$
Work Step by Step
Use long division as shown in the figure, we have $\frac{3x^4-x^2}{x^3-x^2+1}=3x+3 +\frac{2x^2-3x-3}{x^3-x^2+1}$. Thus the quotient is $3x+3$ and remainder is $2x^2-3x-3$
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