Answer
$(-1,1), (0,0), (1,1).
$
Work Step by Step
The graphs of power functions ($f(x)=x^n$, where n is an even integer) always contain the points:
$(-1,1)$ (because $(-1)^n=(-1)^{2k}=1$);
$(0,0)$(because $(0)^n=0$); and
$(1,1)$ (because $(1)^n=1$).
