Answer
$(0,9),(-2,0),(2,0)$
Work Step by Step
We are given the equation:
$9x^2+4y=36$
Rewrite the equation:
$4y=-9x^2+36$
$y=-\dfrac{9}{4}x^2+9$
Determine the intercepts:
$x=0\Rightarrow y=-\dfrac{9}{4}(0^2)+9=9$
$y=0\Rightarrow -\dfrac{9}{4}x^2+9=0$
$\dfrac{9}{4}x^2=9$
$x^2=4$
$x=\pm 2$
The points are: $(0,9),(-2,0),(2,0)$