Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 3 - Linear and Quadratic Functions - Chapter Review - Cumulative Review - Page 165: 5

Answer

$y=-\dfrac{1}{2}x+\dfrac{13}{2}$

Work Step by Step

We are given the line: $y=2x+1$ Let $y=mx+b$ be the equation of the line we are looking for. The slope of the line $y=2x+1$ is 2. Because the two lines are perpendicular, we have: $m\cdot 2=-1$ Determine $m$: $m=-\dfrac{1}{2}$ We determine the equation of the line using the slope $m$ and the point $(3,5)$: $y-5=-\dfrac{1}{2}(x-3)$ Put the equation in slope-intercept form: $y=-\dfrac{1}{2}x+\dfrac{3}{2}+5$ $y=-\dfrac{1}{2}x+\dfrac{13}{2}$ Use the points $(3,5)$ and $\left(0,\dfrac{13}{2}\right)$ to graph the line:
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