Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 3 - Linear and Quadratic Functions - Chapter Review - Cumulative Review - Page 165: 4


$y=-2x+2$ See graph

Work Step by Step

We are given the points: $(-1,4)$ $(2,-2)$ Determine the slope of the line: $m=\dfrac{-2-4}{2-(-1)}=\dfrac{-6}{3}=-2$ Determine the slope-intercept form of the line: $y-(-2)=-2(x-2)$ $y+2=-2x+4$ $y=-2x+4-2$ $y=-2x+2$ Graph the line using the two points:
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