Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 3 - Linear and Quadratic Functions - Chapter Review - Chapter Test - Page 164: 4

Answer

$x=-1,3$ See graph.

Work Step by Step

Step 1. Given $f(x)=x^2+3x$ and $g(x)=5x+3$, let $f(x)=g(x)$ to get $x^2+3x=5x+3$ or $x^2-2x-3=0$ Step 2. Factor and solve the equation $(x-3)(x+1)=0$, thus $x=-1,3$ and $y=-2,18$ or $(-1,-2),(3,18)$ Step 3. See graph.
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