Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 3 - Linear and Quadratic Functions - 3.5 Inequalities Involving Quadratic Functions - 3.5 Assess Your Understanding - Page 160: 7

Answer

$(-2,5)$.

Work Step by Step

Step 1. Factor the inequality to get $(x-5)(x+2)\lt0$ Step 2. Identify the boundary points $x=-2,5$ which separate the number line into three intervals: $(-\infty,-2),(-2,5),(5,\infty)$ Step 3. For each interval, choose a test value and test the inequality, use $x=-3,0,6$ and we have the result as $False, True, False$. Step 4. Thus the solution interval is $(-2,5)$.
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