Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 3 - Linear and Quadratic Functions - 3.3 Quadratic Functions and Their Properties - 3.3 Assess Your Understanding - Page 146: 52

Answer

$f(x)=-(x-2)^2+3$

Work Step by Step

If the vertex of a graph is at $(m,n)$ then the vertec form for the quadratic function is $f(x)=a(x-m)^2+n$. According to the picture the vertex of the graph is at $(2,3)$, hence the quadratic function becomes $f(x)=a(x-2)^2+3$. The point $(0,-1)$ is on the graph, hence if we plug in the values we get: $-1=a(0-2)^2+3 \\-1=4(a)+3\\ -4=4a \\a=-1$ Thus, the equation of the function is $f(x)=-(x-2)^2+3$.
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