Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 3 - Linear and Quadratic Functions - 3.1 Properties of Linear Functions and Linear Models - 3.1 Assess Your Understanding - Page 128: 41

Answer

a) $[9075,36900]$; b) $\$2546.25$ c) Independent: $x$; dependent: $T$ d) See graph e) $\$27,500$

Work Step by Step

We are given the function: $T(x)=0.15(x-9075)+907.50$ As $x$ is between 9075 and 36,900, the domain of the function $T$ is: $[9075,36900]$ b) Determine $T(20,000)$: $T(20,000)=0.15(20,000-9075)+907.50=2546.25$ c) The independent variable is $x$, while $T$ is dependent on $x$. d) Compute $T(9075)$ and $T(36900)$: $T(9075)=0.15(9075-9075)+907.50=907.50$ $T(36,900)=0.15(36,900-9075)+907.50=5081.25$ Graph the linear function $T$ on the domain $[9075,36900]$, using the points $(9075,907.50)$ and $(36900,5081.25)$. e) Solve the equation $T(x)=3671.25$: $0.15(x-9075)+907.50=3671.25$ $0.15(x-9075)+907.50-907.50=3671.25-907.50$ $0.15(x-9075)=2763.75$ $x-9075=\dfrac{2763.75}{0.15}$ $x-9075=18,425$ $x-9075+9075=18,425+9075$ $x=27,500$
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