Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 2 - Functions and Their Graphs - Chapter Review - Chapter Test - Page 116: 8

Answer

$19.$

Work Step by Step

General formula for average rate of change from $a$ to $b$: $\frac{f(b)-f(a)}{b-a}.$ Hence here: $\frac{f(4)-f(3)}{4-3}=\frac{(3\cdot4^2-2\cdot4+4)-(3\cdot3^2-2\cdot3+4)}{1}=\frac{(48-8+4)-(27-6+4)}{1}=\frac{(44)-(25)}{1}=19.$
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