Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 2 - Functions and Their Graphs - Chapter Review - Chapter Test - Page 116: 3

Answer

At $-1$: $1$. The domain is all real numbers except $-2$.

Work Step by Step

We plug in $x=-1$ to $f(x)$ to get $f(-1)=\frac{-1+2}{|-1+2|}=\frac{1}{|1|}=\frac{1}{1}=1.$ We know that the denominator cannot be $0$, hence $|x+2|\ne0\\x+2\ne0\\x\ne-2.$ Thus the domain is all real numbers except $-2$.
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