Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 2 - Functions and Their Graphs - 2.3 Properties of Functions - 2.3 Assess Your Understanding - Page 80: 76

Answer

(a) odd. (b) $-16$

Work Step by Step

(a) Given $f(x)=-x^3+12x$, we have $f(-x)=-(-x)^3+12(-x)=-(-x^3+12x)=-f(x)$ Since $f(-x)=-f(x)$, then the function is odd. (b) With a local maximum of $16$ at $x=2$, then, since the function is odd, we can locate a local minimum to be $f(-2)=-16$.
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