Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 2 - Functions and Their Graphs - 2.1 Functions - 2.1 Assess Your Understanding - Page 57: 38



Work Step by Step

Solve for $y$: $x+y^2=1\\y^2=1-x\\y=\pm \sqrt {1-x}.$ This relation is s not a function, because a distinct $x$-value corresponds to two different $y$-values. For example, $(-3, 2)$ and $(-3, –2).$
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