Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 2 - Functions and Their Graphs - 2.1 Functions - 2.1 Assess Your Understanding: 35

Answer

The equation does not define $y$ as a function of $x$.

Work Step by Step

Solve for $y$: $y ^2 = 4-x^2$ $y=± \sqrt{4-x^2}$ This relation is s not a function, because a distinct x - value corresponds to two different y-values. For example, (0, 2) and (0, –2)
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