Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 14 - A Preview of Calculus: The Limit, Derivative, and Integral of a Function - Chapter Review - Chapter Test - Page 908: 6



Work Step by Step

$$\lim_{x\to \frac{\pi}{4}}\frac{\tan{x}}{1+\cos^2{x}}\\=\frac{\tan{\frac{\pi}{4}}}{1+\cos^2{\frac{\pi}{4}}}\\=\frac{1}{1+(\frac{\sqrt2}{2})^2}\\=\frac{1}{1+\frac{1}{2}}\\=\frac{1}{\frac{3}{2}}=\frac{2}{3}.$$
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