Answer
$\frac{1}{3}$
Work Step by Step
If $x$ approaches $2$ from above, then $|x-2|=x-2$. Thus $$\lim_{x\to 2^+}\frac{|x-2|}{3x-6}\\=\lim_{x\to 2^+}\frac{x-2}{3(x-2)}\\=\frac{1}{3}$$
Precalculus (10th Edition)
by Sullivan, Michael
Published by
Pearson
ISBN 10:
0-32197-907-9
ISBN 13:
978-0-32197-907-0
Chapter 14 - A Preview of Calculus: The Limit, Derivative, and Integral of a Function - Chapter Review - Chapter Test - Page 908: 2
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