Chapter 14 - A Preview of Calculus: The Limit, Derivative, and Integral of a Function - 14.1 Finding Limits Using Tables and Graphs - 14.1 Assess Your Understanding - Page 877: 45

$\approx 1.60$

We have to determine the limit: $\displaystyle\lim_{x\rightarrow 2} \dfrac{x^3-2x^2+4x-8}{x^2+x-6}$ We use a graphing utility to compute the limit. The result is: $\displaystyle\lim_{x\rightarrow 2} \dfrac{x^3-2x^2+4x-8}{x^2+x-6}\approx 1.60$