Precalculus (10th Edition)

$\approx 4.00$
We have to determine the limit: $\displaystyle\lim_{x\rightarrow -1} \dfrac{x^3+x^2+3x+3}{x^4+x^3+2x+2}$ We use a graphing utility to compute the limit. The result is: $\displaystyle\lim_{x\rightarrow -1} \dfrac{x^3+x^2+3x+3}{x^4+x^3+2x+2}\approx 4.00$