Precalculus (10th Edition)

Published by Pearson
ISBN 10: 0-32197-907-9
ISBN 13: 978-0-32197-907-0

Chapter 11 - Systems of Equations and Inequalities - Chapter Review - Cumulative Review - Page 797: 8


Center: $(1,-2)$ Radius: $4$ See graph

Work Step by Step

We are given the circle: $x^2+y^2-2x+4y-11=0$ Put the equation in standard form: $(x-h)^2+(y-k)^2=r^2$ $(x^2-2x+1)-1+(y^2+4y+4)-4-11=0$ $(x-1)^2+(y+2)^2=16$ Identify $h,k,r$: $h=1$ $k=-2$ $r=\sqrt{16}=4$ The circle has center $(1,-2)$ and radius 4. Graph the circle:
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